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Alla [95]
3 years ago
7

40% of the children in a sports club play badminton. 25% of the children who play badminton also play squash. There are 11 child

ren in the club who play both badminton and squash.
How many children are there in the sports club altogether?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

There are 110 children total in the sports club

Step-by-step explanation:

To get this answer, its actually easier than it seems. You might need a calculator however.

First you start with the 11 children who play both badminton and squash, then, you divide that by 0.25 (25%) to get 44.

Next you take 44 and divide it by 0.4 (40%) to get 110.

And there you go! If you want to make sure you got it right simply start with 110 and multiply it by 0.4 then multiply the number/decimal you get by 0.25. You should get 11 to confirm your answer :)

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A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i
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Answer:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

\hat p=\frac{36}{100}=0.36 estimated proportion of people who take R supplement

p_o=0.39 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:  

Null hypothesis:p=0.39  

Alternative hypothesis:p \neq 0.39  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

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For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

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