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2 years ago

How to solve quadratic equation with brackets

Mathematics

2 answers:

lisabon 2012 [21]2 years ago

7 0

Yes I agree the guy above

shtirl [24]2 years ago

6 0

Answer:

Solving Quadratic Equations

Put all terms on one side of the equal sign, leaving zero on the other side.
Factor.
Set each factor equal to zero.
Solve each of these equations.
Check by inserting your answer in the original equation.

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The temperature in degrees Celsius can be expressed by the function C(f)=59(f−32)C(f)=59(f−32) where f is the temperature in deg

Fiesta28 [93]

$\dfrac{5}{9}\cdot (55-32)=\dfrac{5}{9}\cdot 23=\dfrac{115}{9}\approx 13^\circ C$

4 0

2 years ago

A regular octagon has a radius of 6 ft and a side length of

Svetlanka [38]

Answer:

<h2>Area of the regular octagon is approximately 102ft²</h2>

Step-by-step explanation:

Given the radius and length of a side of regular octagon as shown;

radius = 6ft and length of side = 4.6ft

Area of a regular octagon is expressed as $A = 2(1+\sqrt{2} )a^{2}$ where a is the length of one side. Given a = 4.6ft

Area = $A = 2(1+\sqrt{2} )(4.6)^{2}\\$

$= 2(1+\sqrt{2} )*21.16\\= (2+2\sqrt{2})*21.16\\ = 4.83*21.16\\= 102.20ft^{2} \\$

Area of the regular octagon is approximately 102ft²

3 0

2 years ago

PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line

ella [17]

Answer:

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

7 0

2 years ago

Does the point (6, 0) satisfy the equation y = x2?

shtirl [24]

Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.

Y = 6^2 = 36

36 is not 0 so (6,0) is not a solution

6 0

2 years ago

Read 2 more answers

Which statement best describes the solution to the equation below ?

SIZIF [17.4K]

Im going to say option 1

8 0

2 years ago

How to solve quadratic equation with brackets​

How to solve quadratic equation with brackets