We know that 5/6 is way more than 1/2 so we will be safe is we chose a fraction that has a denominator of 8 and is half or less
4/8, 3/8,2/8 and 1/8 are all safe bets and are less than 5/6
so is 5/8 because there is a rule that says is two fractions have the same numerator, the one with the smaller denominator is larger 5/6 > 5/8
Even 6/8 is smaller. If you change it to a decimal 6/8 = 3/4 = .75 5/6 = .8333....
.833..> .75 so we have lots of fractions we can write:
1/8, 2/8, 3/8, 4/8 5/8 and 6/8
<span>7/8 </span>is not<span> because of different rule. If the numerators and denominator of two fractions are the same distance apart the larger pair is greater.</span>
<span>Notice in 7/8, the 8 is one more than 7 and in 5/6, the 6 is one more than 5 (notice that the smaller number in each pair was in the numerator). 7/8>5/6</span>
Answer : I think this is a linear function.
Step-by-step explanation:
I hope you get this correct !
Answer:
1/8;17/20;But I don't really understand take them out separately or at the same time, the secondary answer is 17/180
Step-by-step explanation:
P1=5/40=1/8,that means there is 5 different balls in forty balls you can take,the situation you take the ball is 40,but the situation you take the different one is five so the possibility you take the different on is 5/40=1/8.
the next answer is just like how we do during the first question
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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.