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tester [92]
2 years ago
9

Select the correct answer.

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
7 0

Answer:

2.80 years

Step-by-step explanation:

beacause it is simple that it will take option B . You

don't have to worry .

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If a given data point is (1,4) and the line of best fit is y = 1.5x + 3.25, what's the residual value?
Svetlanka [38]

Answer:

The residual value is -0.75

Step-by-step explanation:

we know that  

The residual value is the observed value minus the predicted value.

RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE]

where

Predicted value.--> the predicted value given the current regression equation

Observed value. --> The observed value for the dependent variable.

in this problem

we have the point (1,4)

so

The observed value is 4

<em>Find the predicted value  for x=1 </em>

y =1.5(1)+3.25=4.75

predicted value is 4.75

so

RESIDUAL VALUE=(4-4.75)=-0.75

4 0
3 years ago
Due to weather mark walk to school day of the 20 days in february what would be the fraction representation for the number of da
nekit [7.7K]

Tbe question doesn't state the number of days he walked to school out of 20 school days in the

Month of February.

Answer:

Kindly check explanation

Step-by-step explanation:

To. Obtain the fractional representayion for the number of days he walked to school ;

Let the number of days he walked to school = 10 (this is an hypothesized value)

Number of school days in February = 20

Fraction = 10 /20 = 0.5

The percentage of times walked to school : multiply the fraction obtained above by 100%

0.5 * 100% = 50%

Just put the desired value and proceed uSing the steps described above.

8 0
3 years ago
Find the product.<br> (a2)(2a3)(a2 – 8a + 9)
eimsori [14]
Answer: -72a^3 +108a^2
Collect like terms
(2a)(6a)(2a-8a+9)= (2a)(6a)(-6a+9)=12a^2(-6a+9)
= -72a^3 +108a^2
3 0
3 years ago
Round 418 to the nearest ten.
marissa [1.9K]

Answer:

The answer should be 420.

~

Step-by-step explanation:

7 0
2 years ago
After all your hard work studying for Algorithms you, Alice and Bob end up stuck in a room full of deadly zombies! Luckily you h
shutvik [7]

Answer:

The most important quantity to consider in order to answer this question is the arrival time of the zombies from their initial position, which is the quotient between their distance to the visitors, divided the zombie's speed.

See explanation below.

Step-by-step explanation:

Part 1)

What is crucial to know is what is the time at which each zombie would reach Alice and Bob, and that is given by the quotient between the distance away each zombie is, divided by the zombie's speed:

speed=\frac{distance}{time} \\time=\frac{distance}{seed} \\t_i=\frac{d_i}{s_i}

Then, it is this quotient for each zombie, that one has to estimate given the input values distance and speed, and it is the output "time" (t_i) for each zombie, what we need to analyze so as to prioritize an order regarding which zombie to kill first.

Part 2)

Shooting the closest zombie first is not a good idea, since the speed of that closest zombie may be much slower than another zombie further away, but with much larger speed. Again, the important value to analyze is the time that it would take each zombie to reach Alice and Bob.

Part 3)

Shooting the fastest zombie first is not a good idea either, because that fastest zombie could be located very far away from the visitors, and other zombies closer by may reach them first.

Part 4)

The order that should be used to kill the zombies is given by the value of the time to reach Bob and Alice based on the quotient distance (di) over speed (si) explained in Part 1). The zombie that shows smallest time should be shot first, and then the others in increasing order of time value.

Part 5)

Notice that the individual zombie information is not presented in the question, but the student should be able to calculate the quotients for each zombie, and considering that there could be at most one shot every second, estimate the number of seconds that the time for each zombie in increasing order would allow until the addition of shooting time per second in the appropriate order cannot match the arrival time of the zombies that are left.

One should count number of seconds from the first shot (to the zombie with shortest arrival time), and then increase in one unit (one shot per second), to the following zombie with slightly larger arrival time), and so on, until the addition of seconds (one second per shot and per increasing arrival time of zombie) exceeds the next zombie arrival time.

7 0
3 years ago
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