Answer:
5/3 or 10/12
Step-by-step explanation:
Answer:Third one
Step-by-step explanation:
If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x.
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair.
Answer:
Step-by-step explanation:
Provide problems and we're here to help.
Answer: Company A would be a better deal for number of minutes over 200
Step-by-step explanation:
Let x represent the number of minutes that you would use with either company A or company B.
Company A has a monthly charge of $10 plus 5¢ a minute for each minute of long distance calls. It means that the cost of x minutes of long distance call is
10 + 0.05x
Company B has a monthly charge of $8 plus 6¢ a minute for long distance calls. It means that the cost of x minutes of long distance call is 10 + 0.05x
8 + 0.06x
For Company A to be a better deal, it means that
10 + 0.05x < 8 + 0.06x
10 - 8 < 0.06x - 0.05x
2 < 0.01x
0.01x > 2
x > 2/0.01
x > 200
