Answer:
A. sec =12/13×
B. COS =12/13×
C. tan =12/5✓
D. sin =12/13 ✓
Step-by-step explanation:
we know,
using Pythagoras formula,
p=12,h=13 ,b=?
h^2 =p^2 +b^2
b=5
so tan = p/b
=12/5
sin=p/h and cosec= h/p
D. sin =12/13
The circle's equation tells us that it is centered at the origin and that the radius is the square root of 5, which in numbers is 2.23 rounded. That means that any points within that radius are inside the circle and any points outside that radius are outside the circle, which tells us our answers to A and C. A is well within the radius at (-1,1) and C is way outside at (4, -8). Now let's look at B. We have our equation and we also have a radius squared of 5, so let's fit the x and the y values of the point (-2, 1) into that equation and see if what we get is equal to the radius squared that they give us.
If
then
should = 5. It does, so that coordinate for B lies directly on the circle.
Answer with explanation:
If you want to Draw a Right Triangle Circumscribed about a circle, Draw a Right Triangle by taking Pythagorean Triplet.
Now, Draw Perpendicular Bisector of any of two sides.The Point where the two bisectors meet is center of the circle.
To find the center we have used the theorem, line from the mid point of the chord passes through the center of the circle.
From the center , that is at the point where the perpendicular bisectors meet,draw a circle Passing through three vertices of Right Triangle.
Both are irrational. pick the first option.