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Svetllana [295]
3 years ago
7

The green shape is a dilation of the black shape. What is the scale factor of the dilation?

Mathematics
2 answers:
kow [346]3 years ago
7 0

Answer:

4

Step-by-step explanation:

damaskus [11]3 years ago
7 0

Answer:

Step-by-step explanation:

The left most line is 2 units above the x axis on the black shape.

The left most line is 8 units above the x axis on the green shape

the dilation factor is

green / black = 8 / 2

green / black = 4

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The table shows the outputs, y, for different inputs, x:
ASHA 777 [7]
Part A:
Yes, the data represent a function because there is at least one x-value for every y-value.

Part B:
When x=6 in the input-output table, y=14. When x=6 in the relation f(x)=7x-15, f(x)=7(6)-15=27. <span>The equation has a greater value when x=6.

Part C:</span>
Set f(x) equal to 6 in the equation:
6=7x-15
Solve for x:
7x=21
x=3
<span>x=3 when f(x)=6</span>
3 0
3 years ago
Ted, the postman, has 110 letters to deliver. If Ted can deliver 10 letters in 5 minutes,
valina [46]

Answer:

55

Step-by-step explanation:

There are 11 tens in 110, so 11 times 5 is 55.

8 0
3 years ago
What is g if, g + (g + 21) + (2g - 6) = 191
kicyunya [14]

Answer:

g=44

Step-by-step explanation:

(2g+21) + (2g-6)=191

1. Eliminate redundant () :

2g+21+2g-6 =191

2. Subtract numbers:

2g+15+2g=191

Combine like terms:

4g+15=191

4g=176

Divide:

4g/4=146/4

Solve:

g=44

7 0
3 years ago
Read 2 more answers
What is 3 square root -27/64
fiasKO [112]
3 square root is called cube root btw:

cube root of -27/64 is the same as (cube root of -27)/(cube root of 64)

cube root of -27 is -3
cube root of 64 is 4

the anser is -3/4
6 0
3 years ago
Please answer the questions
Naily [24]

Answer:

1/18

Step-by-step explanation:

( {2}^{ - 3}  \times  {16}^{ \frac{1}{2} } ) \div ( {81}^{ \frac{3}{4} }  \times  {27}^{  - \frac{1}{3} } ) \\  \\  =( {2}^{ - 3}  \times  {2}^{ \frac{4 \times 1}{2} } ) \div ( {3}^{ \frac{4 \times 3}{4} }  \times  {3}^{  - \frac{3 \times 1}{3} } ) \\  \\=( {2}^{ - 3}  \times  {2}^{ 2} ) \div ( {3}^{ 3 }  \times  {3}^{  - 1 } ) \\  \\=( {2}^{ - 3 + 2} ) \div ( {3}^{ 3 - 1 }  )  \\  \\  =  {2}^{ - 1}  \div  {3}^{2}  \\  \\  =  \frac{1}{2}  \times  \frac{1}{9}  \\  \\  =  \frac{1}{18}

5 0
2 years ago
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