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Neko [114]
3 years ago
10

Ax-by=c I need help solving this problem

Mathematics
1 answer:
telo118 [61]3 years ago
6 0
Solving for x.
Add by to both sides
Ax=c+by
Divide both sides by a
x=c+by
-------
a
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The two short sides of a triangle are 3 and 4 inches. what is the length of the hypotenuse,in inches?​
disa [49]

Answer:

The length of the hypotenuse is 5 inches.

Step-by-step explanation:

The formula for finding the hypotenuse is a^{2} + b^{2} = c^{2},

with a and be being the two shorter sides of the triangle, while c is the hypotenuse.

Let's plug in our values for a and b and solve.

4^{2} + 3^{2} = c^{2}

16 + 9 = c^{2}

25 = c^{2}

What is the square root of 25? 5.

The length of the hypotenuse is 5 inches.

3 0
3 years ago
Read 2 more answers
Janette went to Tire Mart and paid $122.57 per tire for 4 tires and a flat rate fee for installation for a total of before taxes
storchak [24]
136.71-122.57=14.14 BUTTT 136.71+58=194.71

194.71-122.57=72.14

so its 72.14 (if multiple choice question and thats not on there, do 14.14 ONLY IF)

4 0
4 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
Which answer describes the calculations that could be used to solve this problem?
faltersainse [42]
D. Since we know that 1 ticket = $8 we would multiply to figure out how much 7 tickets were. (7x$8). And to figure out his change you would subtract the ticket amount from $100 :) Hope this helps
4 0
3 years ago
Read 2 more answers
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