The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
<em>x</em>² - x
<em>x</em> = 4
4² - 4
16 - 4 = 12
Hope this helps!
Answer:
Alrighty! So this is what we know:
Slope (m) = (-4)
Co-ordinate (0,3)
Co-ordinate 2 (6,t)
t = ?
Let's find our equation...
y=mx+b <-- just plug what we know in...
3=(-4)0+b
3=0+b
b=3
We just found b! woohoo
Now what is t? t is a value we need to know WHICH IS the y value of a co-ordinate that corresponds to when x is 6, as we know a co-ordinate is expressed as --> (x value, y value).
SO-
t=y
plug it in our equation...
y=mx+b
t=(-4)x+3
t=(-4)(6)+3
t=(-24)+3
t=(-21)
SOOOOOOOO WE HAVE OUR T!! just write a therefore statement like "therefore the value of t is -21." and you're set! hope this helped, any questions? ask in the comment section. :)
Step-by-step explanation:
Answer:
y = -5x + 1
Step-by-step explanation:
y - 6 = -5 (x + 1)
distribute -5 (x + 1) by multiplying
y - 6 = -5x - 5
than add 6 to both sides
y = -5x + 1
