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2 years ago

10

Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0

1 answer:

garri49 [273]2 years ago

3 0

Answer:

take a picture of the problem

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Step-by-step explanation:

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antoniya [11.8K]

Slope intercept form: y= 2x-5

Explanation:
1: Simplify -1 • x to -x
2: Simplify 1 • y to y
3: 1 • x to x
4: Regroup terms
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2 years ago

If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

$x(t) = 3\cos{\pi t}$

What is the first occurrence of a value of t for which x = 0?

This is t when $x(t) = 0$ . So

$x(t) = 3\cos{\pi t}$

$3\cos{\pi t} = 0$

$\cos{\pi t} = \frac{0}{3}$

$\cos{\pi t} = 0$

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

$\arccos{\cos{\pi t}} = \arccos{0}$

$\pi t = \frac{\pi}{2}$

$t = \frac{\pi}{2 \pi}$

$t = \frac{1}{2}$

$t = 0.5$

The first occurence of t for which x = 0 is t = 0.5.

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Tpy6a [65]

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