Answer: 30.48
Step-by-step explanation:
Sum the series of 30.48 + (1/2)(30.48)+ (1/4)(30.48)+(1/8)(30.48)+(1/16)(30.48)+(1/32)(30.48)
Or use an Excel spreadsheet
Answer:
The ratio of their surface areas is 
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is equal and this ratio is called the scale factor
In this problem the scale factor is equal to the ratio 
and
Remember that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
therefore
In this problem the ratio of their surface areas is 
Answer:
y = -4
Step-by-step explanation:
12y + 4 = 8y-12
Subtract 8y from each side
12y - 8y +4 = -12
4y +4 = -12
Subtract 4 from each side
4y +4-4 = -12 -4
4y = -16
Divide by 4
4y/4 = -16/4
y = -4
We know that
area of the tent=length*breath
length=240 cm---convert to m---> 240/100----> 2.40 m
breath=170 cm----convert to m---> 170/100----> 1.70 m
find the area
area=2.40*1.70-----> area=4.08 m²
therefore
the answer is
<span>the friend's statement is incorrect the area is 4.08 m</span>²
Answer:
400 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x
Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x
The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:
1500 = 1000 + 5x
5x = 1500 - 1000
5x = 500
x = 100 minutes.
1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb
Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt
