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3 years ago

Please hellpppp!!! 4-5-6 please

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

4 is C. Multiply by 3

5 is 56 cookies

6 is H. 3/5

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PLEASE HELP WILL MARK BRAINLIEST (if possible).......................Braden bought 18 pencils for $4.50. Let x represent the num

Bingel [31]

Y=4 Because you divide 18 by 4.50 and then just put a point on positive four on your graph.

8 0

3 years ago

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The Shirts For All shop keeps track of the total number of white and tie-dye t-shirts it sells. In one week, 500 shirts were sol

bagirrra123 [75]

Step-by-step explanation:

Cost of white shirt=$15

Cost of tie-dye shirt = $20

Total number of shirts= 500

Total number of white shirts= 200

Cost of white shirts = 200×15=$ 3000

Total number of tie-dye shirts = 300

Cost of tie-dye shirts = 300×20= $6000

Verification:

3000+6000=$9000 proved!

7 0

2 years ago

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6 to the power of 2 equal ?

EleoNora [17]

Answer:

Step-by-step explanation:

Whenever something is to the power of 2, just think of the number multiplied twice :) Hoped this helped.

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2 years ago

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n

Svetradugi [14.3K]

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

The null hypothesis is $H_o : p = 0.015$

The alternative hypothesis is $H_a : p < 0.015$

The sample size is n= 150

Generally in order to use normal sampling distribution

The value $np \ge 5$

$np = 0.015 * 150$

$np = 2.25$

Given that $np < 5$ normal sampling distribution can not be used

8 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = $xyz$

with subject to $x+2y+3z=9$

So, let $z=\dfrac{9-x-2y}{3}$

So, Volume becomes,

$V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}$

Partially derivative wrt x and y we get that

$9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9$

By solving these two equations, we get that

$x=3,y=\dfrac{3}{2}$

So, $z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1$

So, Volume of largest rectangular box would be

$xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5$

Hence, the volume of largest rectangular box is 4.5 units.

4 0

3 years ago