The probability tests to detect the presence of hepatitis B:
P (presence)= 0.97 (true) 0.03 (false)
P (absence)= 0.99 (true) 0.01 (false)
P(infected)=0.0055
P(not infected)= 0.9945
To have an incorrect result:
P[infected and false from P(presence)] + P[not infected and false from P(absence)]
=0.0055*0.03+0.9945*0.01= 0.01011
The answer is<span> 0.01011 </span>
Answer:
y = 3/2x + 6
Step-by-step explanation:
2/3 y - 4 = x
2/3y = x + 4
y = 3/2 * (x + 4)
y = 3/2x + 6
Well all of the coins total to 16. There are 3 quarters so you do 16-3=13. Then divide that by the total number of coins found earlier.
Answer= <u>13
</u> 16 chance to not get a quarter
