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3 years ago

Please help meeee:(((( give explanation

Mathematics

1 answer:

choli [55]3 years ago

8 0

Answer:

5 ( x – 3) = – 3 (2x+5)

5x – 15 = – 6x – 15

5x +6x = – 15 +15

11 x = 0

x =0/11

x =0

I hope I helped you^_^

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A movie is 2hrs and 4 minutes long. The movie starts at 11:45am. When will the movie end?

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The movie will end at 1:49 pm.

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3 years ago

Read 2 more answers

How do I graph -4x+6y=12

eimsori [14]

You have 2 options.

I will show you the most efficient one, but later I will tell you the other.

-4x+6y=12

6y=4x+12

y=4/6x+12

y=2/3x+12

This tells us the point (0,12) as 12 is where it meets the y-axis (that is why you add it)

And then using the slope, 2/3 we can get (2,15) (which is up 3, right 2)

Just graph those, I would show you exactly, but I cannot add attachments sadly.

The other way (which I won’t show it all as the results would end out with the same line) is to fill in x, then y, with 0

So -4*0+6y=12 which means x=0 and you are solving for y and -4x+6*0=12 which means y=0 and you are solving for x

8 0

3 years ago

I need help pleaseeee, anyone?!!

Black_prince [1.1K]

Answer:

a or d

Step-by-step explanation:

5 0

2 years ago

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y

Anestetic [448]

Answer:

$\frac{1}{4180}$

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are $12$ red candies, $12$ blue, $7$ green, $13$ brown, $3$ orange, and $10$ yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total candies in the bag $=57$

Probability that first ball is orange, $P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{3}{57}=\frac{1}{19}$

Probability that second ball is orange, $P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{2}{56}=\frac{1}{28}$

Probability that third ball is green, $P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}$

$=\frac{7}{55}$

Now, probability that first two balls are orange and third is green is

$=P(A)\times P(B)\times P(C)$

$=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}$

$=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}$

$=\frac{1}{4180}$

Hence, probability that first two balls are orange and third is green is $\frac{1}{4180}$

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3 years ago

Approximately how many CDs of 12cm diameter can fit in a rectangular wall which dimensions are 6mx4,8m?

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