The answer is D. The ones on the left are the domain. The ones on the right which the arrows point to are the range
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
Its the last option.
Step-by-step explanation:
f(x) = 4x^3.
f(-x) =
4(-x)^3 = - 4x^3
so f(x) = = -f(x) so the function is odd.
Answer:
Distance between the 2 planes is 17.8km
The bearing of B from A is 162°
Step-by-step explanation: