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nikdorinn [45]
3 years ago
5

13

Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

Distance between the 2 planes is 17.8km

The bearing of B from A is 162°

Step-by-step explanation:

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-g+2(3+g)=-4(g+1) answer please?
RideAnS [48]

Answer:

3+g=- 134

Step-by-step explanation:

5 0
3 years ago
Help me I have so many of these​
Doss [256]

Answer:

3/4

Step-by-step explanation:

dividing by a fraction is the same as multiplying by its reciprocal.

Therefore,

(1/2) / (2/3) = (1/2) * (2/3) = (3/4)

8 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
Solve both pls brainliest
masya89 [10]
Answer 1 is $67.54 and answer 2 is 6. hope this helps. brainliest please
6 0
3 years ago
I need help on this question as soon as possible. If anybody can give me the correct answer I’ll give brainly. I just need help.
3241004551 [841]

Answer:

The solution of the system is (6, 9).

Step-by-step explanation:

Solve one of the variables and substitute the answer for the other variable.

Select one of the problems and solve for x.

3x+y=27

Subtract y from both sides.

3x+-y=27

Divide both sides by three.

x=1/3(-y + 27)

Multiply 1/3 by -y + 27.

x = -1/3y + 9

Replace -y/3 + 9 for x in the other problem 3x-2y=0.

3(-1/3y + 9) - 2y = 0

Multiply 3 by -y/3 + 9.

−y+27−2y=0

Add -y to -2y.

−3y+27=0

Subtract 27 from both sides of the problem.

−3y=−27

Divide both sides by −3.

y=9

Replace 9 for y in x=−1/3​y+9.

x=−1/3*9+9

Multiply −1/3​ times 9.

x=-3+9

Add 9 to -3.

x = 6.

x = 6, y = 9.

3 0
2 years ago
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