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3 years ago

Find the LCM of 6,12 and 15

Mathematics

2 answers:

Karolina [17]3 years ago

4 0

LCM=2×2×3×5=2×6×5=2×30=60

True [87]3 years ago

3 0

<h3>Answer: 60</h3>

Step-by-step explanation:

$\large \boldsymbol{} \sf 6=\bold3\cdot \underline2 \\\\12=\bold3\cdot \underline2\cdot 2\\\\15=5\cdot\bold 3 \\\\ LCM(6 ; 12 ; 15) =\bold{3\cdot 2}\cdot 2\cdot 5=60$

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LenaWriter [7]

Answer:

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

Step-by-step explanation:

we have

$f(t)=Ce^{(-kt)} +20$

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

<em>Find the value of the constant C</em>

we have the ordered pair (4,35)

substitute in the equation and solve for C

$35=Ce^{(-0.0399*4)} +20$

$Ce^{(-0.0399*4)}=15$

$C=15/e^{(-0.0399*4)}$

$C=17.6$

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

For t=0

$f(0)=(17.6)e^{(-k*0)} +20$

$f(0)=17.6 +20$

$f(0)=37.6\ degrees\ Celsius$

therefore

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

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$\csc( \alpha ) = \frac{1}{ \sin( \alpha ) } \\$
------------------
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Find the LCM of 6,12 and 15​

Find the LCM of 6,12 and 15