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coldgirl [10]
3 years ago
7

3. For what value of x is the equation 224 +7 = 2" true?

Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

Step-by-step explanation:

I think it's TRUE but the equation is false.

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Let f(x) = -4x + 7
Tema [17]

g(x) = 2x-6

f(x) = -4x +7

(g•f)(x) = g(f(x))

= 2(f(x)) - 6

= 2 ( -4x+7) -6

= -8x + 14 -6

= -8x +8

now

(g•f)(1) = -8(1) + 8= -8+8

= 0

so option a is answer

4 0
3 years ago
I have 30 minutes to complete this and im stuck so pls help out
dimaraw [331]

Answer:

130

Step-by-step explanation:

its basically the same thing

7 0
3 years ago
Read 2 more answers
F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?
zhuklara [117]

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

6 0
3 years ago
Read 2 more answers
Oblicz.Pamiętaj o kolejności wykonywania działań
SashulF [63]

Answer:

33.275

Step-by-step explanation:

<u>1 step:</u> Difference in brackets

3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}

<u>2 step:</u> 0.75\div\dfrac{1}{3}

0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}

<u>3 step:</u> 1.28\div 0.04

1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}

<u>4 step:</u>

2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}

<u>5 step:</u>

\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275

6 0
3 years ago
9. Travelling at 80 km/h, how far will a car go<br> in 45 mins?
AysviL [449]

Answer:

60

Step-by-step explanation:

distance=80*45/60

=80*0.75

=60km

3 0
3 years ago
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