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Blizzard [7]
2 years ago
10

What is the square root of 16/121 answer has to be a fraction :)

Mathematics
2 answers:
elena55 [62]2 years ago
8 0

Answer:

4/11

Step-by-step explanation:

the square root of 16 is 4 and the square root of 121 is 11

answer is 4/11

dedylja [7]2 years ago
7 0

Answer:

4/11

Step-by-step explanation:

The \sqrt\frac{16}{121} is 0.36 which is in decimal form, so in fraction form that's \frac{4}{11}

Also the \sqrt{16} is 4 and the \sqrt{121} is 11.

I hope this helps!!

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A number is added to 13. The result is then multiplied by 2 to give a new result of 52. What is the number ?
Andreyy89

Hi, so I first I divided 52 by 2 and ended up with 26. 26-13 is 13.

The answer is 13

Check my work 13+13 =26

26 times 2 is 52

5 0
3 years ago
What are the domain and range of the function f(x) = 3x + 5
fredd [130]

Step-by-step explanation:

Here,let x = 1,2,3 and 4

Then,

Domain =(1,2,3,4)

Again,

f(1)= 3*1 + 5

=3 + 5

=8

f(2)=3*2 + 5

=6 + 5

=11

f(3)=3*3 + 5

=9 + 5

=14

f(4)=3*4 + 5

=12 + 5

=17

Therefore, Range=(8,11,14,17)

7 0
2 years ago
7. The cost of renting the party room for 10 people is $117.50. The cost of renting the room is $151.25 for 15 people. Write an
Viktor [21]

Answer:

C = 6.75n + 50

Step-by-step explanation:

The equation for the cost of renting the party room can be written in the form;

C= mn+k ......i

Where C = cost

n = number of people

Substituting the 2 cases into the equation we have,

Case 1

117.5 = 10m + k ......1

Case 2

151.25 = 15m + k .....2

Subtracting eqn 1 from 2 we have

151.25 - 117.50 = 15m - 10m

5m = 33.75

m = 33.75/5 = 6.75

Substituting m = 6.75 into eqn 1, we have

117.50 = 10(6.75) + k

k = 117.5 - 67.50

k = 50

Therefore, rewriting the eqn i, we have

C = 6.75n + 50

5 0
3 years ago
Determine the zeros of f(x)=x^3+7x^2+10x-6
igor_vitrenko [27]
Hello,
x^3+7x^2+10x-6=x^3+3x^2+4x^2+12x-2x-6
=x²(x+3)+4x(x+3)-2(x+3)
=(x+3)(x²+4x-2)
=(x+3)(x+2-√7)(x+2+√7)

zeroes={-3,-2+√7,-2-√7}

4 0
3 years ago
Help please help me with this. ​
boyakko [2]

\pi r^2h

\pi \times 7^2 \times 7

\pi \times 7^3

\displaystyle 343\pi

3 0
3 years ago
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