Question

What are the zeros of the function? f(x) = 8x2 + 2x – 21

Answer 1

X= 3/2 and -7/4
Factored is: (2x-3)(4x+7) you can find zeros by setting each of them to zero

Answer 2

Answer:

$x=\frac{3}{2}$ and $x=-\frac{7}{4}$

Step-by-step explanation:

Since, the zeroes are the input values in which the value of a function is zero,

Here, the given function,

$f(x)=8x^2+2x-21$

For zeroes,

f(x) = 0

$\implies 8x^2 + 2x - 21 =0$

By middle term splitting,

$8x^2 + 14x - 12x - 21=0$

$2x(4x+7) - 3(4x+7)=0$

$(2x-3)(4x+7)=0$

By zero product property,

2x - 3 = 0 or 4x + 7 = 0

⇒ x = 3/2 or x = -7/4

Hence, the zeroes of the given equation are $x=\frac{3}{2}$ and $x=-\frac{7}{4}$