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LekaFEV [45]
8 months ago
13

Door prizes for entrants in a young inventors competition are $100, $50, $25 and $10. In how many ways can the door prizes be aw

arded if there are 23 entrants?.
Mathematics
1 answer:
Over [174]8 months ago
4 0

The total number of ways the prizes are awarded is 8855.

The prizes for entrants in a young inventors competition are $100, $50, $25, and $10.

Which are of total 4 types of prizes.

If there are 23 entrants in the competition the prizes can be awarded in the following ways by using Combinations.

Total number of ways =  ²³C₄

                                    = \frac{23!}{4! * (23 - 4)!}

                                    = 8855

The total number of ways the prizes are awarded is 8855.

To learn more about Combinations click here:

brainly.com/question/13387529

#SPJ4

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2a ³+10=26<br> Show the work on how you got it
Usimov [2.4K]

Answer:

a=2

Step-by-step explanation:

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2 years ago
Which expression is equivalent to 12X + 4X +20?
BabaBlast [244]

Answer:

12x + 4x + 20

4(3x + x + 5)

4(4x+5)

Step-by-step explanation:

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3 years ago
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2 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
2 years ago
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