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77julia77 [94]
3 years ago
8

*need this answered ASAP please. Write the solution to the given inequality in interval notation.

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0
...........................

belka [17]3 years ago
5 0

Step-by-step explanation:

this is the right answer..hope it helped you .

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My mother pays my brother twice as much allowance as she pays me because he cleans the bathrooms. Together we get $24 each week.
Harman [31]

Answer:

Your brother gets $16 and you get $8.

Step-by-step explanation:

first of all what is 16+8=24

first step..i started from 2 and did twice of that wich is 4 but that only got $6

second step.... just keep doing your multiples....

third step....as soon as i got to the number 8 i did twice of that and i got 16 then i added those and i got $24

and that is your answer.

4 0
3 years ago
Write the equation of a line with a slope of 3 and a y-intercept of 1.
noname [10]

Take a look at the image below.

6 0
3 years ago
Can you help me with this please?
N76 [4]
Use a calculator and divide
8 0
3 years ago
Fill in what I haven't filled in
Lelu [443]
11/20=.55 =55% ; 1/400=.0025=.25% ; 5/8=.625=62.5%
7 0
3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
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