<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
130 oz is bigger than 8 pounds because 1 pound is equal to 16 oz
Answer: (x-2)^2+(y+3)^2 = 9Side notes
1) This circle has a center of (2,-3)
2) The radius of this circle is 3
3) The graph is shown in the attached image
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Work Shown:
x^2-4x+y^2+6y+4=0
x^2-4x+y^2+6y+4-4=0-4
x^2-4x+y^2+6y = -4
x^2-4x+4+y^2+6y = -4+4 ... see note 1 below
(x^2-4x+4)+y^2+6y = 0
(x-2)^2+y^2+6y = 0
(x-2)^2+y^2+6y+9 = 0+9 ... see note 2 below
(x-2)^2+(y^2+6y+9) = 9
(x-2)^2+(y+3)^2 = 9note 1: I'm adding 4 to both sides to complete the square for the x terms. You do this by first taking half of the x (not x^2) coefficient which in this case is -4. So take half of -4 to get -2. Then square this result to get 4
note 2: Like with note 1, I'm completing the square. What's different this time is that this is for the y terms now. The y coefficient is 6. Half of this is 3. Square 3 to get 9. So this is why we add 9 to both sides.
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So
the equation in standard form is (x-2)^2+(y+3)^2 = 9Note how
(x-2)^2+(y+3)^2 = 9
is equivalent to
(x-2)^2+(y-(-3))^2 = 3^2
So that second equation listed above is in the form (x-h)^2+(y-k)^2 = r^2
where
h = 2
k = -3
r = 3
making the center to be (h,k) = (2,-3) and the radius to be r = 3
The graph is attached.
The position of the particle as function of time is given as
The velocity as function of time is
A graph of f(t) versus t and of v(t) versus t is shown below.
The velocity increases in the intervals t = (2, 6) and t = (10, 14) and with a periodicity of 8.
In the range t = [0, 16], the velocity increases in the interval t = (2,6)∪(10, 14).
Answer: (2,6)∪(10,14)
<u>Corrected Question</u>
The Venn diagram shows three types of numbers: odd (O), even (E), and prime (P). Which is represented by Ø?
(A) O ⋃ P (B)E ∩ P (C)O ⋃ E (D)E ∩ O
Answer:
(D) E ∩ O
Step-by-step explanation:
The Venn diagram is reproduced and attached below.
In the Venn diagram, the sets of Odd(O) and Even(E) numbers are disjoint, i.e. there is no intersection.
We can also say the intersection of sets O and E is the empty set.
Therefore: E ∩ O is represented by the empty set Ø.
Generally speaking, a number cannot be even and odd at the same time.
The correct option is D
