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3 years ago

2.23 reapting (2 and 3) decimal as a fraction

Mathematics

1 answer:

andrew11 [14]3 years ago

5 0

Answer:

221/99

Step-by-step explanation:

2.23 repeating equals x

223.23 repeating equal 100x

subtract x from 100x and you get 99x=221

divide by 99 on both sides of the equal sign and you get x=221/99

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Rewrite 19/19 as a whole number

Elis [28]

The answer is 1.

Because if you simplify (divide) 19/19 you get one.

4/4 would also be 1. Any number divided to itself will always be 1.

Whereas 30/15 would be 2 because thirty divided by fifteen is 2

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3 years ago

A student solved this problem and said the answer was 78.

katovenus [111]

It's B.) The student’s answer is not reasonable. Estimation: 170 + 90 = 260

8 0

3 years ago

Read 2 more answers

Factor the following perfect square trinomial

yKpoI14uk [10]

25x^2+10x+1

25x^2+5x+5x+1

5x(5x+1)+1(5x+1)

(5x+1)(5x+1)

(5x+1)^2

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4 years ago

Write -0. 18 repeating as a fraction in simplest form.

galina1969 [7]

Answer:

-2/11

Step-by-step explanation:

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3 years ago

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago