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Allushta [10]
3 years ago
9

If (fx)=5x, what is f^-1(x)

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

x/5

Step-by-step explanation:

To get the inverse function you need to leave the x alone and then switch variables ( f(x) = y)

f(x) = 5x

y = 5x

y/5 = x

Now that x is alone you switch the x for y and the y for x and you get:

x/5 = y

And this new y is the inverse function of f(x) ( f^-1(x))

f^-1(x) = x/5

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Computing the limit directly:

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Alternatively, you can recognize the limit as being equivalent the derivative of <em>f(x)</em> at <em>x</em> = 2, in which case differentiating and plugging in 2 gives

<em>f'(x)</em> = 2<em>x</em> + 1   =>   <em>f'</em> (2) = 5

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Step-by-step explanation:

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The sum of two numbers is 30. the first number is 1/5 of the second number. what are the numbers?
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Same question
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subsitute
y/5+y=30
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