3 years ago

Plz solve this question

Mathematics

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

Step-by-step explanation:

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Where does the line through (1, 0, 1) and (4, −3, 3) intersect the plane x + y + z = 6?

Irina-Kira [14]

Parametrically for real t the line is

$(x,y,z) = (1-t)(1,0,1) + t(4,-3,3)$

$(x,y,z) = (1,0,1) + t(4-1,-3-0,3-1)$

$(x,y,z) = (1,0,1) + t(3,-3,2)$

That's three equations; we substitute into

$x+y+z=6$

$(1+3t)+(0-3t) + ( 1+2t)=6$

$2t=4$

$t=2$

$(x,y,z) = (1,0,1) + 2(3,-3,2) = (7,-6,5)$

The intersection is a single point (7,-6,5).

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so we have to find 0.12 times of $1,520.50

0.12 * 1520.50=182.46

so they will set aside $182.46 to travel

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3 years ago

Which is the graph of the inverse secant function?

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Plz solve this question​

Plz solve this question