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miv72 [106K]
2 years ago
10

My question is down there

Mathematics
1 answer:
slavikrds [6]2 years ago
7 0
I don’t really see the question ?
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M
den301095 [7]

Answer:

Step-by-step explanation:

m∠JXM + m∠NXP = 180° - m∠MXN = 90°

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3 years ago
How do i Write in Digits the fifty five hundredths​
grandymaker [24]

fifty five hundredths is equal to 0.55

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2 years ago
Read 2 more answers
C=100+25h solve for h
aivan3 [116]

Answer:

h=(c/25)-4

Step-by-step explanation:

c-100 = 25h.   "/25"

(c/25)-4 = h

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earnstyle [38]
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8 0
3 years ago
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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