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3 years ago

Please help me out!!!!!!

Mathematics

1 answer:

Anna71 [15]3 years ago

3 0

Volume of a pyramid is (L * w * h) / 3

L=10 and w=10

h can be found by using the Pythagorean theorem:

divide the base by 2 and we get 5. Then we have that the hypotenuse is 13 and the bottom of the right triangle we formed is 5. a= sqrt(c^2-b^2)

a=h=12

we plug these numbers into the formula for the volume of a pyramid and get:

400

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What is an equation of the line that is perpendicular to y=−23x+5 and passes through the point (2, 11) ?

hichkok12 [17]

Answer:

The equation would be y = 1/23x - 251/23

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -23. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 1/23.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 11 = 1/23(x - 2)

y - 11 = 1/23x - 2/23

y = 1/23x - 251/23

5 0

3 years ago

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The graph shows the distance a bicyclist traveled from a starting point in 10-second increments. Which of these is closest to th

myrzilka [38]

Answer:

C. 10 m/s

Step-by-step explanation:

3 0

3 years ago

How would I start to solve this? Y=-1/3-1

statuscvo [17]

Answer:

Y = -4/3

Step-by-step explanation:

Subtract 1 from -1/3.

Y = -1/3 - 1

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6 0

3 years ago

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ANEK [815]

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8 0

3 years ago

How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l

musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - α) % confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The formula to compute the sample size is:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}$

(1)

Given:

$\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97$

Thus, the minimum sample size required is 97.

(2)

Given:

$\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385$

Thus, the minimum sample size required is 385.

(3)

Given:

$\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604$

Thus, the minimum sample size required is 9604.

8 0

3 years ago