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AlexFokin [52]
3 years ago
10

#3 Q is the midpoint of PR, PQ = 2x, and PR = 8x - 12. Find X, PQ, and PR.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0

Answer:

x = 3, PQ = 6 , PR = 12

Step-by-step explanation:

Given Q is the midpoint of PR , then

PQ = QR = 2x

PR = PQ + QR , that is

8x - 12 = 2x + 2x

8x - 12 = 4x ( subtract 4x from both sides )

4x - 12 = 0 ( add 12 to both sides )

4x = 12 ( divide both sides by 4 )

x = 3

Then

PQ = 2x = 2 × 3 = 6

PR = 8x - 12 = 8(3) - 12 = 24 - 12 = 12

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Answer:

i)x=0,x=1

ii)

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Step-by-step explanation:

so I did not use the graphs actually.

for the answer to question i), i wrote out the equation as given:

3x^2-3x+2=2

then, i subtracted the two from the right side of the equation to make the equation set equal to 0, and I got:

3x^2-3x+2-2=+2-2, which becomes 3x^2-3x=0

then, I used the quadratic method of taking out the greatest common factor, which in this case is 3x, and the equation becomes:

3x(x-1)=0

finally, for this equation, I set 3x=0 and x-1 =0 to get the solutions to this equation, as shown below

3x=0(divide both sides by 3 to get)x=0

x-1=0(add 1 to both sides to get)x=1

now for the second equation, I had no other choice but to use the quadratic formula to find the solutions.

so I set up the quadratic formula as shown:

\frac{-(-4)+ or -\sqrt{(9-4)^2)-4(-2)(3)} }{2(3)}

from there the equation gets simplified down to:

\frac{4+ or -\sqrt{16-4(-6)} }{6}

simplifying the formula even further gives us:

\frac{4+ or -\sqrt{40} }{6}

if we simplify the equation one last time, we get:

\frac{2}{3} + or -\frac{\sqrt{40} }{6}

therefore, the solutions to this equation are:

\frac{2}{3} +\frac{\sqrt{40} }{6}\\ \frac{2}{3} - \frac{\sqrt{40} }{6}

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Remember that

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