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3 years ago

(-2)^2+26/(-8+6)*2-(-10)-2^2

Mathematics

1 answer:

ziro4ka [17]3 years ago

5 0

Answer:

Step-by-step explanation:

$(-2)^{2} +\frac{26}{-2} * 2-(-10)-2^{2} \\4 - \frac{26}{2} *2-(10)-4\\4-26+10-4\\-22+10-4\\-12-4\\-16$

#MathIsFun ;)

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i) 3a+2b=9 /*3

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An animal feed to be mixed from soybean meal and oats must contain at least 168 lb of protein, 27 lb of fat, and 14 lb of minera

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Answer:

The animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

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Step-by-step explanation:

The given parameters can be summarized as:

$\begin{array}{cccc}{} & {x} & {y} & {Total} & {Protein} & {70} & {21} & {168} &{Fats}& {9} & {7} & {27} & {Minerals} & {7} & {1} & {14}& {Cost} & {21} & {7} & {} \ \end{array}$

Where: x = Soybeans and y = Oats.

So, the system of equations are:

$70x + 21y = 168$

$9x +7y = 27$

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The best way to solve this, is using graph

Plot the following equations on a graph, and get the points of intersection:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

From the attached graph, we have:

$(x_1,y_1) = (1.636,2.545)$

$(x_2,y_2) = (1.775,1.575)$

$(x_3,y_3) = (2.023,1.256)$

Substitute each of the values of x's and y's in the cost function to get the minimum cost:

$Cost = 21x + 7y$

$(x_1,y_1) = (1.636,2.545)$

$Cost = 21 * 1.636 + 7 * 2.545$

$Cost = 52.171$

$(x_2,y_2) = (1.775,1.575)$

$Cost = 21 * 1.775 + 7 * 1.575$

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$(x_3,y_3) = (2.023,1.256)$

$Cost = 21 * 2.023 + 7 * 1.256$

$Cost = 51.275$

The values of x and y that gives the minimum cost is:

$(x_2,y_2) = (1.775,1.575)$

and the minimum cost is:

$Cost = 48.3$

Hence, the animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

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