Answer:
x=6
Step-by-step explanation:
24=4x
divide both by 4
equals 6
First, you should graph the points. For the first number, called the X-Axis, you should to the right or left, and for the second number, called the Y-Axis, you should go up or down.
To find the distance between Point A and Point C, you should simply just count the number of intersections between them (4).
Angle B is a right angle because if the triangle is bisected at B, it will leave a right angle on either side. Therefore, to label it, you should simply just draw a line through Point B all of the way to line (A,C).
The type of triangle you have drawn is an isosceles, because it has 2 equal angles and 2 equal sides.
We know both of the sides that are unknown will be the same because the triangle is bilateral. Then, we can use the bisection we made earlier to solve for the unknown sides using Pythagorean Theorem. Since earlier, we know the entire bottom is 4, we know half of the bottom is 2. We can also see that the height of the triangle is 2. We then plug those numbers into the Pythagorean Theorem (A^2*B^2=C^2) which makes the value of C^2=16. We then take the square root of C^2 and 16 to see that both unknown sides are 4.
X = 2
A square has 4 sides. To get the perimeter of a square, you could multiply the length of one side by 4.
One side of the larger triangle is x inches plus an additional 8 inches, which can be written as (x+8)
To get the perimeter of the larger square, multiply the expression (x+8) by 4. The question states the larger square’s perimeter is 40 inches.
You end up with this equation: 4(x + 8) = 40
To solve first distribution 4 into (x + 8).
4x + 32 = 40 | subtract 32 from both sides
4x = 8 | divide each side by 4
x = 2 inches
So the side length of the original square is 2 inches. To check your work, go back and plug x = 2 into the original equation. 8 in + 2 in = 10 inches, and 10 inches x 4 = 40 inches, so x = 2 is the solution
Answer: Oc. 28
Step-by-step explanation:
5^2=25
3+5^2=3+25=28
X = 6iy-4y+83-66i/13
y= 14+9i/2-x-3xi/2
