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andrew-mc [135]

2 years ago

14

Answer the statistical measures and create a box and whiskers plot for the following set of data.

1 answer:

suter [353]2 years ago

4 0

Answer:

Minimum = 5

Lower Quartile (Q1) = 6

Median = 9

Upper Quartile (Q3) = 12

Maximum = 15

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The coordinates of point L on a coordinate grid are (−2, −4). Point L is reflected across the y-axis to obtain point M and acros

Alex787 [66]

M(2,-4), N(-2,4)
.......................................................

4 0

2 years ago

An important problem encountered by personnel directors and others faced with the selection of the best in a finite set of eleme

SVETLANKA909090 [29]

Answer:

1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the engineers are selected is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

10 engineers selected from a set of 20.

5 best, from a set of 5.

Other 5, from a set of 20-5 = 15.

$D = C_{5,5}*C_{15,5} = \frac{5!}{5!(5-5)!}*\frac{15!}{5!(15-5)!} = 3003$

Totao outcomes:

10 engineers selected from a set of 20.

$T = C_{20,10} = \frac{20!}{10!(20-10)!} = 184756$

Probability:

$p = \frac{D}{T} = \frac{3003}{184756} = 0.0163$

1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

5 0

2 years ago

What’s the gcf (greatest common factor) of this expression

love history [14]

Answer:

x

Step-by-step explanation:

just look at them what do they have in common?

5 0

2 years ago

Read 2 more answers

On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?

bonufazy [111]

Answer:

Birds $F_b=14.3\%$

Gerbils $F_g=42.9\%$

Fish $F_f=21.4\%$

Hamsters $F_h=21.4\%$

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds $n_b=2$

Number of gerbils $n_g=6$

Number of fish $n_f=3$

Number of hamsters $n_h=3$

Generally the frequency for birds $F_b$ is mathematically given b

$F_b=\frac{n_b}{n}*100$

$F_b=\frac{2}{14}*100$

$F_b=14.3\%$

Generally the frequency for Gerbils $F_g$ is mathematically given b

$F_g=\frac{n_g}{n}*100$

$F_g=\frac{6}{14}*100$

$F_g=42.9\%$

Generally the frequency for fish $F_f$ is mathematically given b

$F_f=\frac{n_f}{n}*100$

$F_f=\frac{3}{14}*100$

$F_f=21.4\%$

Generally the frequency for fish $F_h$ is mathematically given b

$F_h=\frac{n_h}{n}*100$

$F_h=\frac{3}{14}*100$

$F_h=21.4\%$

5 0

2 years ago

Can someone help me with this?

Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$

Therefore, number of terms is 6

6 is the right answer.

3 0

2 years ago