Honestly the answer might be divide by 5. It may not be right tho. Sorry if It is wrong.
Answer:
-10, -2, 5
Step-by-step explanation:
First, you can start by making a table.
<u>Negative | Positive</u>
-10 | 5
-2 |
The positive number is obviously the greatest, so now we look at the negative numbers. If the numbers were on a number line, -10 would be more to the left than -2, so it's the least. That leaves -2, which is greater than -10 but less than 5.
Answer:
1. x=6
2. C <-26
3. p<6
4. -5x-44
Step-by-step explanation:
1. 2x = 3(x-2) - 3(x-6)
Distribute
2x= 3x-6 -3x+18
Combine like terms
2x =12
Divide by 2
2x/2 =12/2
x=6
2. C+6<-20
Subtract 6 from each side
C+6-6 < -20-6
C <-26
3. -5p > -30
Divide by -5. Remember to flip the inequality when dividing by a negative
-5p/-5 < -30/-5
p<6
4. -4 - 5(X+8)
Distribute
-4 -5x-40
Combine like terms
-5x-44
Answer:
Step-by-step explanation:
<u>Eigenvalues of a Matrix</u>
Given a matrix A, the eigenvalues of A, called 
are scalars who comply with the relation:
Where I is the identity matrix
![I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix is given as
![A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D)
Set up the equation to solve
![det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%20%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Expanding the determinant
![det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3-%5Clambda%265%5C%5C8%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Operating Rearranging
Factoring
Solving, we have the eigenvalues
The answer to 89+27+11 is 127
