The miles he traveled by plane is nine times greater than the miles traveled by automobile. If the total is 600 miles, then the total distance traveled by automobile would be 60 miles, making the total traveled by airplane 540 miles.
Given that the function g(x)=x-3/x+4, the evaluation gives:
- g(9) = 6/13.
- g(3) = 0.
- g(-4) = undefined.
- g(-18.75) = 1.07.
- g(x+h) = x+h-3/x+h+4
<h3>How to evaluate the function?</h3>
In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:
When g = 9, we have:
g(x)=x-3/x+4
g(9) = 9-3/9+4
g(9) = 6/13.
When g = 3, we have:
g(x)=x-3/x+4
g(3) = 3-3/3+4
g(3) = 0/13.
g(3) = 0.
When g = -4, we have:
g(x)=x-3/x+4
g(-4) = -4-3/-4+4
g(-4) = -1/0.
g(-4) = undefined.
When g = -18.75, we have:
g(x)=x-3/x+4
g(-18.75) = -18.75-3/-18.75+4
g(-18.75) = -15.75/-14.75.
g(-18.75) = 1.07.
When g = x+h, we have:
g(x)=x-3/x+4
g(x+h) = x+h-3/x+h+4
Read more on function here: brainly.com/question/17610972
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Answer:
-3/5 or -0.6
Step-by-step explanation:
To be written in standard form, the exponents need to be in order from largest to smallest.
The answer is: a. −3x^5 + 4x^3 + 10x^2
Answer:
A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.
The given equation consisting of variable , m is
![\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})](https://tex.z-dn.net/?f=%5Cfrac%7B2%20m%7D%7B2%20m%2B3%7D%20-%5Cfrac%7B2%20m%7D%7B2%20m-3%7D%3D1%5C%5C%5C%5C%202%20m%5B%5Cfrac%7B1%7D%7B2%20m%2B3%7D%20-%5Cfrac%7B1%7D%7B2%20m-3%7D%5D%3D1%5C%5C%5C%5C%202%20m%5Ctimes%20%5Cfrac%7B%5B2%20m-3%20-2%20m-%203%5D%7D%7B4m%5E2-9%7D%3D1%5C%5C%5C%5C%20-6%20%5Ctimes%202%20m%3D4%20m%5E2%20-9%5C%5C%5C%5C%204%20m%5E2%20%2B1%202%20m%20-9%3D0%5C%5C%5C%5Cm%3D%5Cfrac%7B-12%20%5Cpm%5Csqrt%7B12%5E2-4%20%5Ctimes%204%20%5Ctimes%20%28-9%29%7D%7D%7B2%5Ctimes%204%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B-12%20%5Cpm%20%5Csqrt%20%7B144%2B144%7D%7D%7B8%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B-12%20%5Cpm%20%5Csqrt%20%7B288%7D%7D%7B8%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B-12%20%5Cpm%2012%20%5Csqrt%7B2%7D%7D%7B8%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B3%7D%7B2%7D%5Ctimes%28-1%20%5Cpm%20%5Csqrt%7B2%7D%29)
None of the two solution
, is extraneous.
Here, L.H.S= R.H.S
Option A: 0→ extraneous
