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Travka [436]
3 years ago
6

Explain how to form a linear combination to eliminate the variable y for this system. 2x - 3y = 3

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
Alright, this is an easy one!

So we are trying to get rid of the y value so the first equation has -3y.  The second equation has 2y.  What values would make these equal.

A.) 2*-3y = -6y and 3 * 2y = 6y.

Now take -6y + 6y and that gives you 0.

Thus, the answer is A.) <span>Multiply the first equation by 2 and the second equation by 3. </span>
Darya [45]3 years ago
4 0

Answer:

Option (a) is correct.

To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.

Step-by-step explanation:

Given system of equations,  2x - 3y = 3   and 5x + 2y = 17

We have to form a linear combination to eliminate the variable y for this given system.

Consider the given system

 2x - 3y = 3 .......(1)  

5x + 2y = 17 ........(2)

Since, we have to eliminate y from the given system.

This can be done when we make the coefficient of y in both equation same.

So, we Multiply the first equation by 2 and the second equation by 3.

Thus, we get,

 2x - 3y = 3 .......(1)       × 2

⇒ 4x - 6y = 6   .....(3 )

5x + 2y = 17 ........(2)      × 3

⇒ 15x + 6y = 51  .....(4)

Now , add (3) and (4) , we get,

4x - 6y +(15x + 6y) = 6 + 51

On simplify, we get

20x = 57

Which is completely in terms of x only and y is eliminated.

Thus, To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.

Option (a) is correct.

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(4x-1)=(5x-8)
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4(7)-1= 27

5(7)-8= 27

So the answer is 27

<span>MN = 27</span>

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4 years ago
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Let f(x)=cos(arctanx). What is the range of f?
Alenkasestr [34]
-π/2 < arctan(x) < π/2

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3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
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Harrizon [31]

Answer:

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Step-by-step explanation:

The absolute value, or the distance of a number from zero has to equate to 5. This means that -5 or 5 can be the answer since -5 is 5 spaces from zero and 5 is 5 spaces from zero on a number line.

7 0
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Peter and John went shopping and spent ratio 2:3 If Peter spent $500 how much did John spend?
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