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Travka [436]
3 years ago
6

Explain how to form a linear combination to eliminate the variable y for this system. 2x - 3y = 3

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
Alright, this is an easy one!

So we are trying to get rid of the y value so the first equation has -3y.  The second equation has 2y.  What values would make these equal.

A.) 2*-3y = -6y and 3 * 2y = 6y.

Now take -6y + 6y and that gives you 0.

Thus, the answer is A.) <span>Multiply the first equation by 2 and the second equation by 3. </span>
Darya [45]3 years ago
4 0

Answer:

Option (a) is correct.

To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.

Step-by-step explanation:

Given system of equations,  2x - 3y = 3   and 5x + 2y = 17

We have to form a linear combination to eliminate the variable y for this given system.

Consider the given system

 2x - 3y = 3 .......(1)  

5x + 2y = 17 ........(2)

Since, we have to eliminate y from the given system.

This can be done when we make the coefficient of y in both equation same.

So, we Multiply the first equation by 2 and the second equation by 3.

Thus, we get,

 2x - 3y = 3 .......(1)       × 2

⇒ 4x - 6y = 6   .....(3 )

5x + 2y = 17 ........(2)      × 3

⇒ 15x + 6y = 51  .....(4)

Now , add (3) and (4) , we get,

4x - 6y +(15x + 6y) = 6 + 51

On simplify, we get

20x = 57

Which is completely in terms of x only and y is eliminated.

Thus, To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.

Option (a) is correct.

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help 112. if k is a positive integer, then for every value of k, the sum of the k smallest distinct odd positive integers is equ
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Hello,

\sum_{i=0}^{k-1}\ (2*i+1)=2*\sum_{i=0}^{k-1}\ i +\sum_{i=0}^{k-1}\ 1\\&#10;&#10;= \dfrac{k*(k-1)}{2} +k=k^2-k+k=k^2

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