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3 years ago

Please how do I find the answer

Mathematics

1 answer:

loris [4]3 years ago

3 0

Answer:

7 of it is 12

Step-by-step explanation:

you have to plus the top ones

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What is 28 over 36 in simplest form

Amanda [17]

28/36 has a greatest common factor of 4.
So, yo can divide the top and bottom by 4.

28 divided by 4/36 divided by 4
7/9

The answer is 7/9

7 0

3 years ago

Read 2 more answers

-12/8+(-0.75)=? <br><br> And <br><br> 4.3+ (-5/3)=?

stiks02 [169]

-12/8+(-0.75)=2.25

and

4.3+ (-5/3)=2.6333333

4 0

3 years ago

,,sarah is building a birdhouse the nail she uses are one inch long.the wood board is 1 foot long . how many times smaller are t

tamaranim1 [39]

The board is 12x larger in length than the nails. (Since the width of the board and nails are unknown, I am assuming you mean the length, not area difference)

3 0

3 years ago

Read 2 more answers

A random sample of the actual weight of 5-lb bags of mulch produces a mean of 4.963 lb and a standard deviation of 0.067 lb. If

dsp73

Answer: B) 4.963±0.019.

Step-by-step explanation:

Confidence interval for population mean ( when population standard deviation is not given) is given by :-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = Sample mean

n= Sample size

s= sample standard deviation

t* = critical t-value.

As per given:

n= 50

Degree of freedom = n-1 =49

$\overline{x}= 4.963\ lb$

s= 0.067 lb

For df = 49 and significance level of 0.05 , the critical two-tailed t-value ( from t-distribution table) is 2.010.

Now , substitute all values in the formula , we get

$4.963\pm (2.010)\dfrac{0.067}{\sqrt{50}}\\\\ 4.963\pm (2.010)(0.0094752)\\\\ 4.963\pm0.019045152\approx4.963\pm0.019$

Hence, a 95% confidence interval for the mean weight (in pounds) of the mulch produced by this company is $4.963\pm0.019$ .

Thus , the correct answer is B) 4.963±0.019.

7 0

3 years ago

use the pythagorean theorem to find the missing side length. 2 write sin, cosine, tangent of each angel.

Harlamova29_29 [7]

Answer:

1) $x=5\sqrt{3}$

2) $sin(a)=5\sqrt{3}/14$

$sin(b)=11/14$

$cos(a)=11/14$

$cos(b)=5\sqrt{3}/14$

$tan(a)=5\sqrt{3}/11$

$tan(b)=11/5\sqrt{3}$

Step-by-step explanation:

The Pythagorean Theorem is:

$a^{2}=b^{2}+c^{2}$

Where a is the hypotenuse and b and c are the legs.

The missing side lenght is one of the legs, then you must solve for one of them. Therefore, this is:

$x=\sqrt{(14yd)^{2}-(11yd)^{2}}=5\sqrt{3}yd$

MEASURE OF ANGLE:

Keep the identities on mind:

$sin\alpha=opposite/hypotenuse$

$cos\alpha=adjacent/hypotenuse$

$tan\alpha=opposite/adjacent$

Susbstitute values, then:

$sin(a)=5\sqrt{3}/14$

$sin(b)=11/14$

$cos(a)=11/14$

$cos(b)=5\sqrt{3}/14$

$tan(a)=5\sqrt{3}/11$

$tan(b)=11/5\sqrt{3}$

4 0

4 years ago

Read 2 more answers

Please how do I find the answer​

Please how do I find the answer