My friend takes 10 cards at random from a 52-card deck, and places them in a box. Then he puts the other 42 cards in a second, i

Question

3 years ago

6

My friend takes 10 cards at random from a 52-card deck, and places them in a box. Then he puts the other 42 cards in a second, i

dentical box. He hands me one of the two boxes and asks me to draw out the top card. What is the probability that the first card I draw will be the Ace of Spades?

Mathematics

2 answers:

IRINA_888 [86] · Answer 1 · 2021-12-26T13:42:48+03:00

IRINA_888 [86]3 years ago

5 0

Answer:

Step-by-step explanation:

The card you draw is just as likely to be the ace of spades as that can be selected from any other from 51 cards.So the chance of it being the ace of spades is 1/52

Wittaler [7] · Answer 2 · 2021-12-26T15:09:42+03:00

Answer:

$P=\frac{1}{52}$

Step-by-step explanation:

Notice that each box doesn't have any advantage at all, because he didn't place the ace of spades at a specific box, that's a random outcome. That means the general probability doesn't change, it's the usual.

It's like choosing a card form a 52-card deck. In other words, splitting the deck doesn't change your probabilities, it's the same scenario.

Now, we know that there's only one Ace of Spades and the total outcomes are 52. So, the probability is

$P=\frac{1}{52}$