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Serggg [28]
4 years ago
6

My friend takes 10 cards at random from a 52-card deck, and places them in a box. Then he puts the other 42 cards in a second, i

dentical box. He hands me one of the two boxes and asks me to draw out the top card. What is the probability that the first card I draw will be the Ace of Spades?
Mathematics
2 answers:
IRINA_888 [86]4 years ago
5 0

Answer:


Step-by-step explanation:

The card you draw is just as likely to be the ace of spades as that can be selected from any other from  51 cards.So the chance of it being the ace of spades is 1/52

Wittaler [7]4 years ago
5 0

Answer:

P=\frac{1}{52}

Step-by-step explanation:

Notice that each box doesn't have any advantage at all, because he didn't place the ace of spades at a specific box, that's a random outcome. That means the general probability doesn't change, it's the usual.

It's like choosing a card form a 52-card deck. In other words, splitting the deck doesn't change your probabilities, it's the same scenario.

Now, we know that there's only one Ace of Spades and the total outcomes are 52. So, the probability is

P=\frac{1}{52}

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3 0
3 years ago
Explain how to use the distributive property to find the product 3 x 4 1/5
NikAS [45]

Answer:

12.6

Step-by-step explanation:

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5 0
3 years ago
solve using the addition method. what is the x-value of the solution to the system? 2x-3y=-1 3x+4y=24
AysviL [449]

Answer:

x-value is 4

Step-by-step explanation:

2x-3y=-1

3x+4y=24

We can solve the equation by eliminating y

We multiply the first equation by 4 and the second by 3

4(2x-3y=-1 )

3(3x+4y=24)

8x -12y = -4

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Then we add the two equations;

8x -12y = -4

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17x = 68

  x = 4

Thus the x-value is 4

4 0
4 years ago
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