Answer:
Step-by-step explanation:
(8x²-18x+10)/(x²+5)(x-3)
express the expression as a partial fraction:
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5
both denominator are equal , so require only work with the nominator
(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)
8x²-18x+10= x²A+5A+bx²+cx-3bx-3c
combine like terms:
x²(A+b)+x(-3b+c)+5A-3c
(8x²-18x+10)
looking at the equation
A+b=8
-3b+c=-18
5A-3c=10
solve for A,b and c (system of equation)
A=2 , B=6, and C=0
substitute in the value of A, b and c
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5
(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)
(8x²-18x+10)/[(x^2+5)(x-3)] =
<h2>2/(x-3)+6x/x²+5</h2>
(4x+2)/[(x²+4)(x-2)]
(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)
(4x+2)=a(x²-2)+(bx+c)(x-2)
follow the same step in the previous answer:
the answer is :
<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>
24
Percentage Calculator: 18 is what percent of 75? = 24.
Step-by-step explanation:
a=110. x,55
y=180-(x+75)=50
w,75
b,110
x,40
y,30
Step-by-step explanation: To add and subtract fractions with the same denominator, or bottom number, place the 2 fractions side by side. Add or subtract the numerators, or the top numbers, and write the result in a new fraction on the top. The bottom number of the answer will be the same as the denominator of the original fractions.
Answer:
The result of the integral is 81π
Step-by-step explanation:
We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:
Finding the curl of F.
Given 
we have:
Working with the determinant we get
Working with the partial derivatives
Integrating using Stokes' Theorem
Now that we have the curl we can proceed integrating
where the normal to the circle is just 
since the normal is perpendicular to it, so we get
Only the z-component will not be 0 after that dot product we get
Since the circle is at z = 3 we can just write
Thus the integral represents the area of a circle, the given circle 
has a radius r = 3, so its area is 
, so we get
Thus the result of the integral is 81π
