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Maslowich
3 years ago
14

Write an inequality for x that would give this rectangle an area of at least 300ft sq2

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

Step-by-step explanation:

P≥300

300≤P

P=2(L+W)

300≤2(L+W)

L=3

W=x+5

300≤2(3+x+5)

300≤2(8+x)

divide both sides by 2

150≤8+x

minus 8 both sides

142≤x

x is at least 142

width is at least 147

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Algebra 1 please help!! 35 points!!!
Zanzabum

Answer:

x intercept: 5

y intercept: 50

Step-by-step explanation:

  • let us plot the graph for better understanding.
  • we will represent f(x) on y-axis so, the equation will become: y= 50-10x
  • the equation is of the form : y=mx+c

[where, m: slope of the line

c : y-intercept ]

  • meaning of x intercept:  the x-coordinate of the point where the line meets x-axis
  • meaning of y intercept:  the y-coordinate of the point where the line meets y-axis
  • the line y= 50-10x has slope of -10 and it passes through (0,50)

[ (0,50) lies on the line only. substitute and check if the point satisfies the above line equation]

  • by seeing the graph in the attachment and by the definitions given above, we can say that,

x intercept:  5

y intercept: 50

4 0
3 years ago
A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the
Katena32 [7]

1st character = 26 possibilities ( 26 letters in the alphabet)

2nd character = 26 possibilities

3rd character = 26 possibilities

4th character = 10 ( 10 special characters)

26 x 26 x 26 x 10 = 175,760 combinations

6 0
3 years ago
Of the $77.84 direct-deposited from Problem 3, you have 50% placed into a savings account. How much is deposited in the saving a
In-s [12.5K]

Answer:

38.92 dollars

Step-by-step explanation:

3 0
3 years ago
the tangent line to the curve y=x^3-6x^2-34x-9 has slope 2 at two points on the curve. find the two points
hichkok12 [17]
\bf y=x^3-6x^2-34x-9\implies \cfrac{dy}{dx}=3x^2-12x-34
\\\\\\
\stackrel{\textit{slope of 2}}{2}=3x^2-12x-34\implies 0=3x^2-12x-36
\\\\\\
0=x^2-4x-12\implies 0=(x-6)(x+2)\implies x=
\begin{cases}
6\\
-2
\end{cases}\\\\
-------------------------------\\\\
\stackrel{y}{f(6)}=(6)^3-6(6)^2-34(6)-9\implies f(6)=-213\\\\\\ (\stackrel{x}{6}~,~\stackrel{y}{-213})
\\\\\\
\stackrel{y}{f(-2)}=(-2)^3-6(-2)^2-34(-2)-9\implies f(-2)=27\\\\\\ (\stackrel{x}{-2}~,~\stackrel{y}{27})
7 0
3 years ago
What rate of interest compounded annually is required to double an investment<br> in 18 ​years?
andreev551 [17]

Answer:

r=3.93\%

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=18\ years\\ P=x\\A=2x\\ r=?\\n=1  

substitute in the formula above

2x=x(1+\frac{r}{1})^{1*18}  

2=(1+r})^{18}  

Elevated both sides to 1/18

2^{\frac{1}{18}} =1+r

r=2^{\frac{1}{18}} -1

r=0.0393

convert to percentage

Multiply by 100

r=3.93\%

3 0
3 years ago
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