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Lina20 [59]
3 years ago
15

In a chemical compound there are three parts zinc for every 16 parts copper by mass. A piece of the compound contains 320 g of c

opper. Write and solve an equation to determine the amount of zinc in the chemical compound.
Mathematics
1 answer:
Orlov [11]3 years ago
6 0
<span>Total mass contains 320g copper. How many parts of 16g copper are there of the total mass of 320g copper? 320/16 = 20. There are 20 portions of 16g copper. (320/16) * 3 = 60g There are 60g of zinc in the compound.</span>
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Answer:

A: 10.9

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Five percent is the same as 1:20?
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A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
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Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

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P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

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P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

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Is there a easy way to subtract fractions with unlike deiomaters
Angelina_Jolie [31]

Answer:

Yes

Step-by-step explanation:

It's just like adding fractions where you have to find the common denominator so the fractions can be subtracted.

<u>Example</u>

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