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viktelen [127]
3 years ago
8

If 7 + 5 i is a zero of a polynomial function P(x) with real coefficient, then which is also a zero for P(x)

Mathematics
2 answers:
zhuklara [117]3 years ago
8 0

Answer:

ppap

Step-by-step explanation:

fhfhhffhff my name is denish paudyal

Bas_tet [7]3 years ago
8 0

Answer:

7 - 5i

Step-by-step explanation:

complex zeros occur as conjugate pairs , thus if 7 + 5i is a zero, then

7 - 5i is also a zero

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Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?
Oliga [24]

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and NO = \frac{1}{2}KL

Therefore segment NO is parallel to the segment KL.

6 0
3 years ago
A rectangle has a length of 6 cm and a width of 3 cm. Each side is doubled in length. What is the ratio of the areas of the two
valentina_108 [34]

Area  1 = 6 x 3 = 18

Area 2 = 12 x 6 = 72

Ratio = 18 : 72

Ratio = 1 : 4

5 0
3 years ago
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Write an equation of a line that passes through the point (3,2) and is parallel to the line y=3x-4
disa [49]
Parallel lines should have the same slope. Therefore, you know which point it passes through and the slope. Plug in the points and slop into slope-intercept form to find b. Please refer to the picture.

8 0
3 years ago
4
taurus [48]

Answer:

x^2 - 2x + 10, option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

i^2 = -1

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

The solutions are:

x_1 = 1 - 3i, x_2 = 1 + 3i

We have to find the polynomial. All option have a = 1. So

(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10

The correct answer is given by option b.

6 0
3 years ago
Which expressions are equivalent to k/5 Choose two answers
lozanna [386]

Answer:

c i think                                                                              

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8 0
3 years ago
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