3 years ago

If 7 + 5 i is a zero of a polynomial function P(x) with real coefficient, then which is also a zero for P(x)

Mathematics

2 answers:

zhuklara [117]3 years ago

8 0

Answer:

ppap

Step-by-step explanation:

fhfhhffhff my name is denish paudyal

Bas_tet [7]3 years ago

8 0

Answer:

7 - 5i

Step-by-step explanation:

complex zeros occur as conjugate pairs , thus if 7 + 5i is a zero, then

7 - 5i is also a zero

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Read 2 more answers

Can someone please show me how 19169000*e^(0.15)= 222712201 When e= 2.7182818284?

Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

$x =19 169 000 \times e^{0.15}$

(a) The direct method

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(b) The indirect method

$\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201$

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3 years ago