Answer:
Option C. Stem Leaves 6 7 7 2 5 8 5 7 9 9 9 0 9 10 0
Option D.
Step-by-step explanation:
The data values are 67, 72, 85, 75, 89, 89, 87, 90, 99 and 100.
Arranging the data values in ascending order
67, 72, 75, 85, 87, 89, 89, 90, 99, 100
The stem and lead plot can be shown under and stem is denoted as "S" whereas leaves are denoted as "L".
S L
6 7
7 2 5
8 5 7 9 9
9 0 9
10 0
The longer row of stem indicates the higher frequencies and so the length of rows are similar to the heights of bars in histogram.
Answer:
Step-by-step explanation:
From the picture attached,
Addition of the blocks in first row is 60
a + a + a + 12 = 60
3a + 12 = 60
3a = 60 - 12
3a = 48
a = 16
For second row,
(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60
4(b + 5) = 60
b + 5 = 15
b = 10
For third row,
(a + b) + c = (b + 5) + (b + 5) + (b + 5)
a + b + c = 3(b + 5)
16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}
26 + c = 45
c = 45 - 26
c = 19
For fourth row,
3c + d = 60
3(19) + d = 60
57 + d = 60
d = 60 - 57
d = 3
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N(
)' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N(
)' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.

Formula for probability of an event E can be observed as:


So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
The vertex is the point (-4, 7).
Answer:
This contradict of the chain rule.
Step-by-step explanation:
The given functions are
It is given that,
According to chin rule,
It means,
is differentiable if f(g(c)) and g(c) is differentiable at x=c.
Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule