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Evgesh-ka [11]
2 years ago
11

Please help! I’ll also give brainliest! Thank you!

Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer: Union of two sets.

Explanation: "An element is in the union of two sets if it is in the first set, the second set, or both. The symbol we use for the union is  ∪ . The word that you will often see that indicates a union is "or".

Your Welcome :-)

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Pleaseeeeee helpppppp
Marysya12 [62]

They are both factors of 15x-10 because 5(3x-2)=15x-10

factor x factor=product.

In this case 15x-10 is the product

5 0
1 year ago
Solve for x eliminate y
AnnZ [28]

Answer:

x = - 6

Step-by-step explanation:

given the 2 equations

3x + 5y = - 13 → (1)

2x - 3y = - 15 → (2)

To eliminate y from the equations we require their coefficients to be equal so that when we add the equations y is eliminated

multiply equation (1) by 3 and equation (2) by 5

9x + 15y = - 39 → (3)

10x - 15y = - 75 → (4)

add (3) and (4) term by term

(9x + 10x) + (15y - 15y) = (-39 - 75 )

19x = - 114 ( divide both sides by 19 )

x = - 6

To find y substitute x = - 6 into either (1) or (2)



6 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
a wheelchair ramp has a rise from the ground of 1 foot. the ramp has a length of 14 feet. to the nearest degree, find the angle
sergey [27]
The mnemonic SOH CAH TOA helps you remember the relevant trig relationship is
   Sin(α) = Opposite/Hypotenuse
   sin(α) = (1 ft)/(14 ft)
   α = arcsin(1/14) ≈ 4°

The angle the ramp makes with the sidewalk is 4°.
6 0
3 years ago
James practiced piano for 48 minutes. Alisa practiced for 5 times as long as James. How many minutes did Alisa practice? How man
wariber [46]
48(5)=n 
when n= the amount of time that Alisa practiced the piano. 
Alisa practiced for 240 minutes.  

48+240= t
Where t stands for total minutes altogether.
In total, they practiced 288 minutes
7 0
2 years ago
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