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jasenka [17]
2 years ago
10

a solution of salt and water is 5 parts of salt to 25 parts of water . express the ratio of the amount of salt to the amount of

water. what percentage is the solution.​
Mathematics
1 answer:
labwork [276]2 years ago
4 0

Answer:

5 to 25 = 1 to 5 = 1/5 = 20%

Step-by-step explanation:

You might be interested in
on halloween kaleb scored 34 pieces of gummi candy. he got 8 times as much sugar candy and 4 times as much chocolate candy. how
Lady bird [3.3K]
We can first find the number of different types of candy he got:

The number of sugar candy he got:

34×8
=272

The number of chocolate candy he got:

34×4
=136

We can then add them all up to find the total pieces of candy he got:

272+136+34
=442

Therefore, the answer is 442.

Hope it helps!
7 0
2 years ago
Can someone explain how you find the percent of a number? Im very confused ‍
viktelen [127]

Answer:

25 Is 25/100 And Means That It Is 25 %

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4 0
2 years ago
What is the height of the following triangle if the area is 60 square meters? Do not round your answer.
olga nikolaevna [1]

Answer: Height = 8 m

Step-by-step explanation: We have to find h...

We're given two values

A = 60

B = 15

60 is equal to 1/2 x 15

Solve for h:

h = 60 / (1/2 x 15)

h = 60 divided by 7.5

h = 8

I hope this helps!

5 0
3 years ago
The table shows the changes from the average water level of a pond over several weeks. Order the numbers from least to greatest.
Verdich [7]
Be more specific with the question that you’re asking bc I will love to help
3 0
3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
3 years ago
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