All categories

3 years ago

Differentiate the following functions with respect to x x³ + 5x² - 2

Physics

2 answers:

3241004551 [841]3 years ago

5 0

Answer:

The answer is 3x² + 10x

Explanation:

d/dx (x³ + 5x² - 2)

= d/dx (x³) + 5 d/dx (x²) - d/dx (2)

= 3x² + 5(2x) - 0

= 3x² + 10x

Thus, The answer is 3x² + 10x

-TheUnknownScientist

lions [1.4K]3 years ago

5 0

Answer:

3x² + 10 x

Explanation:

hope it's helpful

You might be interested in

A 1200 kg car is being driven down a road. If it has 101 kJ of kinetic energy, what is its speed?

algol [13]

Answer:

The solved problem is in the photo. Hope it helps.

5 0

3 years ago

Which is an expression?

Anestetic [448]

Answer:

C. 4+ 3 < 9

Explanation:

3 0

3 years ago

Are the orbits of each ring system the same or different?

bagirrra123 [75]

Answer: they are diffrent

Explanation: because no ring can be the same it would be crazy and every one has there own unecke ring lol

5 0

3 years ago

A simple pendulum takes 128s to complete 40 oscillations what is the time period of the pendulum

Serhud [2]

Explanation:

Parameters

Number of oscillation = 40 oscillations

Time of oscillation = 128s

Formular

Period (T) = No of oscillation

Time taken

T = 128

T=3.2s

3 0

3 years ago

(a) Suppose a meter stick made of steel and one made of invar are the same length at 0°C. What is their difference in length at

dem82 [27]

Explanation:

Given that,

Initial temperature $T_{i}=0^{\circ}C$

Final temperature $T_{f}=48.0^{\circ}C$

Length = 34.0 m

We know that,

Coefficient of linear expansion of Invar is

$\alpha=0.9\times10^{-6}/^{\circ}C$

Coefficient of linear expansion of steel is

$\alpha=12\times10^{-6}/^{\circ}C$

We need to calculate the temperature difference is

$\Delta T=T_{f}-T_{i}$

$\Delta T=48.0-0$

$\Delta T=48.0^{\circ}C$

We need to calculate the change in length of Invar

Using formula of change in length

$\Delta l=l\times\alpha\times\Delta t$

Put the value into the formula

$\Delta l=34\times0.9\times10^{-6}\times48.0$

$\Delta l=0.0014688=1.47\times10^{-3}\ m$

$\Delta l= 1.47\ mm$

We need to calculate the change in length of steel

$\Delta l'=34\times12\times10^{-6}\times48.0$

$\Delta l'=0.019584=19.59\times10^{-3}\ m$

$\Delta l'=19.59\ mm$

Difference in length of two 34.0 m

Long surveyor's tapes is

$\Delta L=\Delta l'-\Delta l$

Put the value into the formula

$\Delta L=19.59-1.47=18.12\ mm$

The difference in length is 18.12 mm.

Hence, This is the required solution.

6 0

3 years ago

Differentiate the following functions with respect to x x³ + 5x² - 2​

Differentiate the following functions with respect to x x³ + 5x² - 2