Answer:
20.6 cm
Explanation:
charge per cm = 0.14 μC
number of electrons (e) =
to get the length of tape pulled we can apply the formula below
length of tape =
therefore we need to find the magnitude of the charge of the electrons
- 1 electron = C
now that we have the magnitude of the charge, we can find the length of the tape
- length of the tape = = 20.6 cm
Answer:
The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. ... These sounds will interfere to produce detectable beats.
Explanation:
Acceleration = change of velocity over the time = (16-4)/8=1.5 m/s^2
Answer:
a) I = 10⁻² W / m², b) β = 104.8 db
Explanation:
a) For this exercise we use the definition of decibels
β = 10 log
where I and Io are the intensities produced and the sound threshold
I₀ = 10⁻¹² W / m²
log \frac{I}{I_o} = β / 10
I = Io
let's calculate
I = 10⁻¹²
I = 10⁻² W / m²
b) each toad produces the same sound for which the total intensity is
I_total = 3 I
I_total = 3 10⁻² W / m²
expressed in decibels
β = 10 log ()
β = 104.8 db