Sorry!
This cannot be answered. We don't have weight, height, etc.
It describes the river water going faster and slower which affects the force on the sediment particles. The heavier particles settle due to smaller force from slower water. The answer is C) The greater the force of the water, the faster the particle accelerates.
Answer:
Fb = 941.76 [N]
Explanation:
La fuerza de flotacion se define como el producto de la densidad del liquido por la aceleración gravitacional y por el volumen desplazado
Fb = Ro*g*V
donde:
Fb = fuerza de flotacion [N] (unidades del Newtons)
Ro = densidad del liquido = 1000 [kg/m³]
g = aceleracion gravitacional = 9.81 [m/s²]
V = volumen desplazado = 0.096 [m³]
Reemplazando:
Fb = 1000*9.81*0.096
Fb = 941.76 [N]
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.
So we have 1/2 MV^2 = MGH
V^2 = 2GH
V = âš2GH
V = âš( 2 * 9.8 * 325)
V = âš 6370
V = 79.81 m/s
