All categories

3 years ago

Please help me i need help with this

Mathematics

1 answer:

Alik [6]3 years ago

3 0

Answer:

what the?

Step-by-step explanation:

You might be interested in

Which transformation map the strip pattern onto itself?

Veseljchak [2.6K]

From the given figure, the transformation the will map the strip unto itself is a horizontal translation and a glide refrection.

5 0

3 years ago

?????????????????????????????

sergeinik [125]

Answer:

B. 3

Step-by-step explanation:

If you were to multiply the top equation by 3 then the x value for the first equation would be 6 and since the bottom equation's x value is -6, if you were to add them, they would cancel eachother off.

LOL hope this makes sense :) Please give brainliest!! Thanks!!

4 0

3 years ago

Tatiana [17]

Answer:

Step-by-step explanation:

6 0

1 year ago

Sorry that the pic is upside down <br>ANSWER IT PLS<br>NO LINKS

ki77a [65]

The answers to that question is 75 degreey

7 0

3 years ago

Assume we need to estimate the mean of a normally-distributed population with great accuracy. Specifically, for significance lev

bulgar [2K]

Answer:

$n = 2662.56\sigma^2$

Step-by-step explanation:

We are given the following in the question:

Significance level = 0.01

Width of interval = 0.1

Population variance = $\sigma^2$

We have to find the sample size so that the width of the confidence interval is no larger than 0.1

$z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58$

Formula for sample size:

$n = \displaystyle\frac{z^2\sigma^2}{E^2}$

where E is the margin of error. Since the confidence interval width is 0.1,

$E = 0.05$

Putting these values in the equation:

$n = \displaystyle\frac{(2.58)^2\sigma^2}{(0.05)^2} = 2662.56\sigma^2$

So, the above expression helps us to calculate the sample size so that the width of the confidence interval is no larger than 0.1 for different sample variances.

4 0

4 years ago