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kolbaska11 [484]
3 years ago
12

Please help me The difference of two numbers is 9. If the larger number is one more than twice the smaller number, find the lage

r number
Mathematics
1 answer:
Helen [10]3 years ago
6 0

Answer:

17

Step-by-step explanation:

Let the larger number be represented by x

Let the smaller number be represented by y

from the question, the next equations can be gotten :

x - y = 9  equation 1

x = 1 + 2y equation 2

Substitute for x in equation 1

1 + 2y - y = 9

1 + y = 9

Collect like terms

y = 9 - 1

y = 8

Substitute for y in equation 1 and solve for x (the larger number)

x - 8 = 9

x = 9 + 8

x = 17

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Phoenix [80]

Answer:

You can just place the 7 instead of the 0 since if you add anything to 0 it is the number you added. then 3 and 6 make 9. so it is 97.

Step-by-step explanation:

30

<u>+67</u>

97

3 0
2 years ago
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37<br> 35<br> Х<br> x = <br><br> What’s the answer?
Ainat [17]

Answer:

12

Step-by-step explanation:

use Pythagorean theorem

37^2 = 35^2 + x^2

x= ±\sqrt[2]{37^2-35^2}

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answer: x = 12

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3 years ago
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Find the derivative of the function by using the Product Rule. Simplify your answer. f(x) = (x - 3)(x + 3)
Morgarella [4.7K]

Answer:

f'(x)=2x

Step-by-step explanation:

Given : Function f(x)=(x-3)(x+3)

To find : The derivative of the function by using the Product Rule ?

Solution :

The product rule of derivative is

\frac{d}{dx}(u\cdot v)=uv'+vu'

Here, u=x-3 and v=x+3

\frac{d}{dx}((x-3)\cdot (x+3))=(x-3)\frac{d}{dx}(x+3)+(x+3)\frac{d}{dx}(x-3)

\frac{d}{dx}((x-3)\cdot (x+3))=(x-3)1+(x+3)1

\frac{d}{dx}((x-3)\cdot (x+3))=x-3+x+3

\frac{d}{dx}((x-3)\cdot (x+3))=2x

Therefore, f'(x)=2x

3 0
3 years ago
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Dafna1 [17]

Answer:

x=3 and x=-1

Step-by-step explanation:

If f(x)=g(x), then 2x+3=x^2:

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2 years ago
5. A local flower shop sells a dozen roses for
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Answer is below

B

12.85*5=64.25

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