1. C
2. B (wanna turn that in on time)
3. C (perfect!)
4. 600,000 (just gotta multiply, and subtract)
5. $22.74
6. C (corresponds kind of with 2 and 3)
7. i don't see the table, i'm sorry..
8. 10
9. C
10. B
hope this helps!
<span>For the answer to the question above bankers right now are looking for a borrower to not spend more than 28-35% of their gross income for housing expenses. Income of $32,000 a year is $2,667 per month. At a presumed 32% rate the maximum allowable mortgage payment is $2,667 x 0.32 = $850 per month. If Ms. Burke has excellent credit, say FICO over 775 and virtually no debts, then $1,000 per month might still be possible.</span>
The answer is 100.48
(If you are actually multiplying by pi rather than 3.14, then the answer is 100.53)
i think the answer should be hyperbole because the font part of the text is quite exaggerating
Answer: 0.55567
Step-by-step explanation:
Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.
i.e.
Let 
and 
are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator 
.
So that, 
Mean 
Standard deviation =
Z-score : ![z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7BX-E%5Bx%5D%7D%7B%5Csqrt%7BVar%5Bx%5D%7D%7D%3D%5Cdfrac%7B0-1%7D%7B7.0156315694%7D%5Capprox-0.14)
Now , The probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-
Hence, the required probability is 0.55567.
