Answer: 23(1/4)
Step-by-step explanation: this is the answer you can star resolving the equation into the parenthesis
(3/6)² + 7 *4 - 5
if we elevate to the power of 2 the values into the parenthesis, we get the following equation.
(9/36) + 7*4 -5
after this we follow with the values into the parenthesis, if you divide 9 over 36 we get the following result
9/36 = 0.25
then we get the following equation
0.25 +7*4 - 5
after that we can resolve the multiplication getting the following equation
0.25 +28 - 5
then if we resolve the subtraction, we will get this result.
28-5 = 23
then we have 0.25 + 23 this equation is equal to 23.25
if you follow the answer will be one with 23, then we get the possible results, if you divide 1/4=0.25
then we get that the result is
23(1/4)
Answer:
A ≈ $500
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Compounded Interest Rate: A = P(1 + r/n)ⁿˣ
- A is final amount
- P is initial (principle) amount
- r is rate
- n is number of compounds
- x is number of years
Step-by-step explanation:
<u>Step 1: Define</u>
P = 230
r = 0.063
n = 365
x = 12
<u>Step 2: Solve for </u><em><u>A</u></em>
- Substitute: A = 230(1 + 0.063/365)³⁶⁵⁽¹²⁾
- Divide: A = 230(1 + 0.000173)³⁶⁵⁽¹²⁾
- Multiply: A = 230(1 + 0.000173)⁴³⁸⁰
- Add: A = 230(1.00017)⁴³⁸⁰
- Exponents: A = 230(2.1296)
- Multiply: A = 489.808
Answer:
X=125/64
Step-by-step explanation:
x^2+4 x-5=0
x^2+4x=5
4x^3=5
x^3=5/4
x=5^3/4^3
x=125/64
Answer:
7.40
Step-by-step explanation:
Divide 185 by 25 to get unit rate
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
