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vitfil [10]
3 years ago
15

Write a subtraction expression using integers that equals -6.

Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

-9 minus -3

Step-by-step explanation:

-9 - (-3) = -9 + 3 = -6

Subtract and keep the sign of the bigger number.

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The domain of discourse is sets. Suppose some predicate Q is true for all elemenst of A: ∀a ∈ A Q(a). Recall the definition of s
Sloan [31]

Answer:

See the step-by-step explanation

Step-by-step explanation:

Let c be any element of C. (I'm not sure wether you have to assume that C is non-empt or not)

C is a subset of B. That means that as c is  in C, it is also in B. (c \in C \Rightarrow  c \in B)

Now, B is a subset of A. It follows that as c \in B \Rightarrow c \in A.

That means c is an element of A. The predicate Q is true for all elements of A, including c.

Because we let c be any element of C, we have proven that the predicate Q is true for all elements in C.

5 0
3 years ago
How do the graphs of the functions f(x) = (Three-halves)x and g(x) = (Two-thirds)x compare?
miss Akunina [59]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

\bold{f(x)= (\frac{3}{2})^x}\\\\\bold{g(x)= (\frac{2}{3})^x}\\

Following are the graph attachment to this question:

The second function, that is g(x)= (\frac{2}{3})^x is not even a function.

Remember that g(x) function is the inverted f(x) function. And when you see this pattern, a reflection on the Y-axis expects you.

Reflection in the axis.

In x-axis:

Increase the function performance by -1 to represent an exponential curve around the x-axis.

In y-axis:

Increase the input of the function by -1 to represent the exponential function around the y-axis.

8 0
3 years ago
Read 2 more answers
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

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2 years ago
Find the slope of each line.
Jlenok [28]

Answer:

5/7

Step-by-step explanation:

8 0
2 years ago
Explain how you can use a quick picture to find 3 x 2.7
Nat2105 [25]
3 x 2.7 is the same as 3 x 3 x 0.9 = 9 x 0.9 = 8.1
8 0
3 years ago
Read 2 more answers
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