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nordsb [41]
3 years ago
11

Use unit rate to find the unknown value. 15/45 = 6/? B Draw a bar model to find the unknown.

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:a

Step-by-step explanation:did it

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The table shows ordered pairs of the function . What is the value of y when ?
worty [1.4K]

the value of y is equal negative

7 0
3 years ago
For the data in the table, does y vary directly with x? If it does, write an equation for the direct variation. x|y 4|28 6| 48|
vazorg [7]
Let's have a look:

2(4)= 8 (this would not work)

5(4)= 20 (this wouldn't work)

7(4)= 28 This does, let's check the others.

7(6)= 42 This does not work.

"D" would be the correct answer.

I hope this helps!
~cupcake
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3 years ago
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Simplify the expression (x12)3
Grace [21]
I think its just 36x
3 0
4 years ago
The typical full-time employee in a particular hotel works a 40-hour week. Last month, the hotel's 80 employees worked a total o
Mila [183]

Answer: There are 25 FTEs.

Step-by-step explanation:

Since we have given that

Number of hour week for full time employee = 40 hours

In a month we know that

Number of weeks = 4

Total number of hours in a month would be

40\times 4\\\\=160\ hours

If in last month, the hotel's 80 employees worked a total of 4000 hours,

So, Full time equivalent workers were employed by the hotel last month would be

\dfrac{4000}{160}\\\\=25

Hence, there are 25 FTEs.

7 0
3 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
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